[Laszlo-user] Forcing a replication manager
Michael Brady
mbrady at appliedminds.com
Wed Jun 20 04:43:26 PDT 2007
Hi Robin,
Looks like this is about what you're doing already, but here's what I
do in that situation:
-----------------------------------------------------------
// There are two possibilities. The "entry" object may a single
// text item, or it may be a replication manager.
// For a single item, just look at it.
// For a replicated list, iterate over the list.
var isSingleItem = entry['getCloneNumber'] == undefined;
if (isSingleItem) {
// When the entry hasn't been replicated,
// its datapath dp can be null.
var hasDp = entry.datapath.p != null;
if (hasDp) {
// Do something with "entry".
}
}
var i = 0;
var currClone = entry.getCloneNumber(i++);
while (currClone != null) {
// Do something with "currClone".
currClone = entry.getCloneNumber(i++);
}
-----------------------------------------------------------
Unfortunately, I don't know of any way to force replication programatically.
If you find a better way, please post it to the list. I'd like to know it.
Cheers,
Michael
Robin Sheat wrote:
> Hi, if I have something like:
>
> <mycomponent datapath="thepath" />
>
> and thepath only matches one thing, no replication manager is used. This means
> that there is extra checking required when interacting with this component,
> as it may be many components contained inside a replication manager, or it
> may be just the component itself, and this state may change when more data
> comes along or gets deleted later.
>
> I'd like to have something that runs through all the potentially replicated
> mycomponent instances when the cloning is done and they've been rendered (in
> this case I want to calculate a value based on them). I can do this fine if
> there's multiple ones (there's an example for this in the docs), however it
> seems I have to also have a separate hook in place in case there's only one
> thing. What I'd like to be able to do is force replication even if there's
> zero or one items being replicated, that way the one bit of code will handle
> them all. Is this possible, or is there another recommended way of doing this
> sort of thing?
>
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