[Laszlo-user] XPath/datapath question

[Henry Minsky]

Maybe something like this, with an intermediate view for each item?

<canvas width="100%" height="80%" debug="true">
  <debug  fontsize="12"/>

 <dataset name="maindata">
   <maindata>
     <item cell1="alpha" cell2="beta"    cell3="gamma" />
     <item cell1="delta" cell2="epsilon" cell3="zeta" />
   </maindata>
 </dataset>
  <grid datapath="maindata:/maindata">
   <view datapath="item[1]/@*">
     <gridtext/>
   </view>
 </grid>


</canvas>


On 7/12/07, Yang <a1pwak602 at sneakemail.com> wrote:
>
> I'd like to do something like the following:
>
>   <dataset name="maindata">
>     <maindata>
>       <item cell1="alpha" cell2="beta"    cell3="gamma" />
>       <item cell1="delta" cell2="epsilon" cell3="zeta" />
>     </maindata>
>   </dataset>
>   <grid datapath="maindata:/maindata">
>     <gridtext datapath="item[1]/@*"/>
>   </grid>
>
> However, this doesn't work. $* returns a set of name-value pairs as a
> dictionary object, not an array of values. Is there any way to get
> this to work?
>
> Similarly, the following doesn't work.
>
>   <dataset name="maindata">
>     <maindata>
>       <item>
>         <cell1>alpha</cell1>
>         <cell2>beta</cell2>
>         <cell3>gamma</cell3>
>       </item>
>       <item>
>         <cell1>delta</cell1>
>         <cell2>epsilon</cell2>
>         <cell3>zeta</cell3>
>       </item>
>     </maindata>
>   </dataset>
>   <grid datapath="maindata:/maindata">
>     <gridtext datapath="item[1]/*/text()"/>
>   </grid>
>
> Thanks for any pointers.
>



-- 
Henry Minsky
Software Architect
hminsky at laszlosystems.com
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