[Laszlo-dev] Confusing idiom: 'foo' in bar && bar['foo']

[Henry Minsky]

What if they mean

'foo' in bar && bar['foo'] != null

?



On Fri, Mar 21, 2008 at 8:43 AM, P T Withington <ptw at pobox.com> wrote:

> I'm not sure how this got started:
>
>   'foo' in bar && bar['foo']
>
> but it is overly-complicated.  If 'foo' is not `in bar`, then
> `bar['foo']` will evaluate to undefined (and be false), so the first
> test is superfluous.
>
> [Filed as LPP-5660]
>



-- 
Henry Minsky
Software Architect
hminsky at laszlosystems.com
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